(2x^2)+(2y^2)+3xy=1

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Solution for (2x^2)+(2y^2)+3xy=1 equation: 


Simplifying
(2x2) + (2y2) + 3xy = 1

Reorder the terms:
3xy + (2x2) + (2y2) = 1

Solving
3xy + (2x2) + (2y2) = 1

Solving for variable 'x'.

Reorder the terms:
-1 + 3xy + (2x2) + (2y2) = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3xy + (2x2) + (2y2) = 0

The solution to this equation could not be determined.

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